0=15x^2+299x-10

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Solution for 0=15x^2+299x-10 equation:



0=15x^2+299x-10
We move all terms to the left:
0-(15x^2+299x-10)=0
We add all the numbers together, and all the variables
-(15x^2+299x-10)=0
We get rid of parentheses
-15x^2-299x+10=0
a = -15; b = -299; c = +10;
Δ = b2-4ac
Δ = -2992-4·(-15)·10
Δ = 90001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-299)-\sqrt{90001}}{2*-15}=\frac{299-\sqrt{90001}}{-30} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-299)+\sqrt{90001}}{2*-15}=\frac{299+\sqrt{90001}}{-30} $

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